Solve by taking the square root of both sides

option B

x = 1 + 3√6  or x = 1 - 3√6

Step-by-step explanation:

Given in the question an equation,

3(x-1)² - 162 = 0

rearrange the x terms to the left and constant to the right

3(x-1)² = 162

(x-1)² = 162/3

(x-1)² = 54

Take square root on both sides

√(x-1)² = √54

x - 1 = ±3√6

x = ±3√6 + 1

So we have two values for x

x = 3√6 + 1    OR  x = -3√6 + 1

step-by-step explanation: