Find the value of y. round answer to the nearest tenth if needed

y = 54.1

Step-by-step explanation:

The big triangle is divided in two: one on  the left and one on the right. Lets start working with the right one.

We know the right triangle is a right triangle with legs 24 and 36, so we can use Pitagoras to find the hypotenuse (h), in a way that:

24^2 + 36^2 = h^2

1872 = h^2

Applying sqr root in both sides:

h = 43.27

So, the hypotenuse measures 43.27 or 43.3.

Now lets do the same with the triangle of the right which legs are 36 and y, lets find it hypotenuse (g):

36^2 + y^2 = g^2

1296 + y^2 = g^2

Now we will pass to the large triangle, which is composed by the left and the right triangles and has legs of 43.3 and g, and the hypotenuse is 24+y. Lets apply Pitagoras:

43.3^2 + g^2 = (24+y)^2

1875 + 1296 + y^2 = 24^2 + 48y + y^2

3171 + y^2 = 576 + 48y + y^2

As we have y^2 in both sides we can eliminate them

3171 + = 576 + 48y

Now subtract 576 in both sides:

3171 -576 = 576 + 48y - 576

2595 = 48y

Divide both sides by 48:

2595/48 = 48y/48

54.1 = y

So, the large hypotenuse measures 54.1+24 = 78.1. Lets verify:

43.3 ^2 + 1296 + 54.2^2 = 6,108.53

And the sqrd root of 6,108.53 is approximately 78.1. Verified

So, we can confirm: y = 54.1

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu