The coefficients corresponding to k = 0, 1, 2, 4 in the expansion of (x+y)^4 are what

The coefficients in increasing order of k are;

1, 4, 6, 4, 1

Step-by-step explanation:

The expansion of (x+y)^4 falls under the category of binomial expansions in which the coefficients are computed using combinations;

For k = 0, the coefficient is;

4 combination 0 = 1

For k = 1, the coefficient is;

4 combination 1 = 4

For k = 2, the coefficient is;

4 combination 2 = 6

For k = 3, the coefficient is;

4 combination 3 = 4

For k = 4, the coefficient is;

4 combination 4 = 1

These values can also be obtained from the Pascal's triangle;

The coefficients always exhibit some degree of symmetry

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: