What are the roots of x2 + 10x + 29 = 0?

a. 5 ± 2i

b. -5 ± 2i

c. 10 + 4i

d. -10 + 4i

B

Step-by-step explanation:

okay so x^2+10x+29=0

subtract 29 from both sides giving you:

x^2+10=-29

next, used (b/2)^2 to create a trinomial square, which will be 5 so you will have:

x^2-10x+(-5)^2=-29+(-5)^2

Then, simplify the equation:

x^2-10x+25=-4

Next, factor into (x-5)^2 which is:

(x-5)^2= -4

Finally, solve for X:

x=5 +/- 2i

overpriced

step-by-step explanation: