Write the sum using summation notation, assuming the suggested pattern continues. 2 - 6 + 18 - 54 + summation of two times negative three to the power of n from n equals zero to infinity summation of two times three to the power of n from n equals zero to infinity summation of two times three to the power of the quantity n plus one from n equals zero to infinity summation of two times negative three to the power of the quantity n minus one from n equals zero to infinity

It's the first choice.

Step-by-step explanation:

The common ratio is -6/2 = 18/-6 = -3.

2*(-3)^0 = 2*1 = 2.

2*(-3)^1 = -6

2*(-3)^2 = 18

2*(-3)^3 = -54.

So in summation notation is

∞

∑ 2(-3)^n

n=0

The sum using summation notation is given by:

Summation of two times negative three to the power of n from n equals zero to infinity.

i.e. numerically it is given by:

The alternating series is given by:

The series could also be written in the form:

i wish i could u

step-by-step explanation:

i wish i could u

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )