What is the product of (11x+11)(4x+6)

44x² + 110x + 66

Step-by-step explanation:

(11x + 11)(4x + 6)

Use F.O.I.L. to complete this

Firsts   (multiply the first number in each set of parenthesis together)

Outsides  (multiply the first number in the first set of parenthesis and the second number in the second set of parenthesis together)

Insides   (multiply the second number in the first set of parenthesis and the first number in the second set of parenthesis together)

Lasts   (multiply the second number in each set of parenthesis together)

Firsts:           11x(4x) = 44x²

Outsides:     11x(6)  =  66x

Insides:        11(4x)  =  44x

Lasts:           11(6)    =   66

Now add them all together:

44x² + 66x + 44x + 66

   44x² + 110x + 66

1/5^2 = 7.56/45

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: