Find the zero(s) of this function: y=x^2-17x+52

The zeroes are {-4, 13}

Step-by-step explanation:

Your best bet here is to determine the zeros using the quadratic formula or "completing the square."

Completing the square,

y = x² - 17x                         +52, or

y = (x - 17/2)² - (17/2)²         +52, or

y = (x - 17/2)² - 289/4          +208/4, or

y = (x - 17/2)²  - 81/4

We set this = to 0, as we want the zeros.  Then:

(x - 17/2)²  - 81/4 = 0, or

x - 17/2 = ±9/2, after having taken the square root of both sides.

Thus, one root is x = 17/2 + 9/2, or 26/2, or 13, and the other is

                             x = 1/2 - 9/2, or -8/2, or -4.

The zeroes are {-4, 13}.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47