If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (c0d)(x)

The answer is (cod)(x) = 4x^2 + 20x - 2

Step-by-step explanation:

In order to find (cod)(x), we need to start with the c(x) equation and then input the d(x) equation for every x in the c(x) equation.

c(x) = 4x - 2

(cod)(x) = 4(x^2 + 5x) - 2

(cod)(x) = 4x^2 + 20x - 2

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)