If for all real values of x, (x + c)(x + 4) = x2 + 8x + 4c, then c = ?

a. 2
b. 4
c. 6
d. 8
e. 10

  B.  4

Step-by-step explanation:

When you perform the multiplication, you get ...

  (x +c)(x +4) = x² + (c+4)x +4c = x² + 8x +4c

Then ...

  c + 4 = 8 . . . . coefficients of x must match

  c = 4 . . . . . matches choice B

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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