Mathematics, 07.10.2019 04:30, valenzueladomipay09u

Solve (x + 2 < 5) ∩ (x - 7 > -6).

1. {x | 1 < x < 3}
2. {x | x < 3 or x > 1}
3. {all real numbers}

Answers: 2

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Solve (x + 2 < 5) ∩ (x - 7 > -6).

1. {x | 1 < x < 3}
2. {x | x <...

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Solve (x + 2 < 5) ∩ (x - 7 > -6). 1. {x | 1 < x < 3} 2. {x | x < 3 or x > 1} 3. {all real numbers}

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Solve (x + 2 < 5) ∩ (x - 7 > -6).

1. {x | 1 < x < 3}
2. {x | x < 3 or x > 1}
3. {all real numbers}