Mathematics
Mathematics, 12.10.2019 00:30, 19cmulett

Enter the coefficients of the fifth taylor polynomial t5(x) for the function f(x) = x5βˆ’3x4+2x2+5xβˆ’2 based at b=1. t5(x)= + (xβˆ’1)+ (xβˆ’1)2+ (xβˆ’1)3+ (xβˆ’1)4+ (xβˆ’1)5. note: this exercise gives a method for writing a polynomial in powers of xβˆ’1 instead of powers of x. this may be useful, for example, if you are interested in the values of the polynomial near x=1 .

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Enter the coefficients of the fifth taylor polynomial t5(x) for the function f(x) = x5βˆ’3x4+2x2+5xβˆ’2...

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