Graph the image of the figure after a dilation with a scale factor of 3 centered at (2,−7) . use the polygon tool to graph the quadrilateral by connecting all its vertices.

  see attached

Step-by-step explanation:

Each point moves 3 times the distance from the center of dilation that it was.

You can compute the new coordinates by ...

  L = P - O . . . . . the length from O to P is P-O for some point P and origin O

Then 3 times that distance is

  3L = 3P -3O

We want to find the point P' that is 3L from O, so we add this distance to the coordinates of O. We get ...

  P' = 3L +O = 3P -3O +O

  P' = 3P -2O

So, for the lower left point A(-2, -7), the dilated image point A' is ...

  A' = 3(-2, -7) -2(2, -7) = (-6, -21) +(-4, 14) = (-10, -7)

That is, ...

  A' = 3A +(-4, 14)

The coordinates of the remaining points can be found similarly.

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On a graph, it is usually fairly easy to count the grid squares in each direction between the point of interest and the center of dilation. The image point is 3 times the distance in each direction (horizontally, vertically).

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

the answer is d

step-by-step explanation: