How can u order rational numbers from least to greatest

Step-by-step explanation:

If your list of numbers includes fractions and/or irrational numbers (such as π), rewrite all of them as decimal fractions:

Decimal fractions are easier to arrange in ascending order.

Ex:  3.2, π, 4

becomes 3.2, 3.14159, 4

and we see that 3.14159 is the smallest number, 3.2 is the middle number and 4 is the greatest.

Working with rational numbers?  As above, rewriting any fractions as decimal fractions will greatly ease the task of arranging your numbers in ascending order.

e. g., 25/2, 12, 15, 2

should be rewritten s 12.5, 12, 15, 2,  

which, arranged in ascending order, comes out to 2, 12, 12.5, 15.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!