Hurry

what is the equation of the line that passes through (0, 3) and (7, 0)?

y=3/7x-3
y=3/7x+3
y=-3/7x+3
y=-3/7x-3

equation of a line passing through from 2 points (x1, y1) and (x2,y2) is given as

y = mx + c

as two points are passing through it so it will satisfy the equation. so putting both points in equation

(x1,y1) = (0,3)

y1 = mx1 + c

3 = m×0 + c

c = 3

putting 2nd point (x2,y2) = (7,0)

y2 = mx2 + c

0 = m× 7 + c

c + 7m = 0

putting value of c from above

3 + 7m = 0

7m = -3

m = -3/7

so putting value of m and c in final equation.

y = mx + c

y = (-3/7)x + 3

so option 3 is your answer

step-by-step explanation: i dont

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol