Solve for x. write both solutions, separated by a comma.

x = -3 and x = 3/2

Step-by-step explanation:

2x^2 + 3x - 9 = 0

2x^2 + 6x - 3x - 9 =0

2x(x + 3) - 3(x + 3) = 0

(2x - 3)(x + 3) = 0

2x - 3 = 0; x = 3/2

x + 3 = 0; x = -3

see explanation

Step-by-step explanation:

given

2x² + 3x - 9 = 0

To factor

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 9 = - 18 and sum = + 3

The factors are + 6 and - 3

Use these factors to split the x- term

2x² + 6x - 3x - 9 = 0 ( factor the first/second and third/fourth terms )

2x(x + 3) - 3(x + 3) = 0 ← factor out (x + 3)

(x + 3)(2x - 3) = 0

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

Solutions are x = - 3,

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!