The diaz family arrived for breakfast at a diner at 8: 45 a. m .they stayed at the diner for 1 hour and 23 minutes. what time did the family leave the diner

10:08 am

Step-by-step explanation:

Time at which Diaz family arrived at the diner = 8:45 a.m

Time for which Diaz family stayed at the diner = 1 hour and 23 minutes

To find the time at which Diaz family leave the diner

Step 1

add minutes

45 + 23

68

as minutes cannot be greater than 60

so,

subtract 60 from it

68 - 60

add one in the number of hours which they had stayed 1+1 = 2

and reminder is the minutes now

= 8

Step 2 :

add hours

8 + 2

10

step 3

join add and minutes

10:08 am

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5

16

step-by-step explanation: