Im really stuck on this can someone

a jet aircraft travels 1416 miles from atlanta to el paso. traveling against the wind, the trip
takes 3.2 hours. the return trip with the wind takes 2.4 hours. find the speed of the aircraft in
still air and the speed of the wind.

Step-by-step explanation:

The equations are

u - v = 1416%2F3.2     (1)   (effective speed flying against the wind)

u + v = 1416%2F2.4     (2)   (effective speed flying with the wind)

where "u" is the aircraft speed at no wind and "v" is the speed of wind.

Simplify (1) and (2):

u - v = 442.5    (3)

u + v = 590.     (4)

Add equations (3) and (4). You will get

2u = 1032.5  >  u = 1032.5%2F2 = 516.25.

Thus we found the speed of the aircraft at no wind. It is 516.25 mph.

Now from equation (4)  v = 590 - 516.25 = 73.75 mph.

Answer.  the speed of the aircraft at no wind is 516.25 mph.  The speed of wind is 73.75 mph.

Solved.  

It is a typical "tailwind and headwind" word problem.  

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: (-6,3)

step-by-step explanation: