> in the following triangle, find the values of the angles b and b'. which are the best approximations to the solutions?

> explain your answer and i'll mark the brainliest!

B=59.58

B'=120.42

Step-by-step explanation:

For the larger triangle, by sin rule, sinB/10=sin45/8.2

sinB=10*sin45/8.2

For the small triangle on the left hand side, by sin rule, sinB'/10=sin45/8.2

sinB'=10*sin45/8.2

So sinB=sinB' but as B'>90, B and B' are supplementary

B=sin^-1(10*sin45/8.2)=sin^-1(0.8623)=59.58

B'=180-B=180-59.58=120.42

18.8 cubic inches.

step-by-step explanation:

volume of a cone = πr²h

r = 1.5 inches

h = 8 inches

pi = 3.14

volume of our cone = × 3.14 × 1.5² × 8 = 18.84 square inches

or equals to 18.8 square inches rounded up to nearest tenth.

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: