Asap 25 pts + brainliest to right/best answer

one real solution

Step-by-step explanation:

We can use the discriminant to find the types of solutions

b^2 -4ac  where    ax^2 +bx+c=0

Since

x^2 -8x+16 =0

we know a=1 b=-8 and c=16

(-8)^2 - 4(1)(16)

64 -64 = 0

If the discriminant > 0 we have two real solutions

If the discriminant = 0 we have 1 real solutions

If the discriminant < 0 we have two complex solutions

Since it equals zero, we have one real solution

One real solution because the answer is

Step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)