Find the area of this shaded region.

9.13

Step-by-step explanation:There are three lines from the center to the sides. So they are all the same. you can see that the radius is 8 from one of the sides. You can find the area of the big triangle by knowing that 2 of the sides are 8 and 360-270=90 and that is a right triangle so we can use the pythagorean theorem to find the hypotenuse. 8^2+8^2=√128. And we can find the area by doing (8^2+8^2)/2=32 so each triangle is 16 units^2. To find out the lengths of the left triangle we have (.5*√128)^2=√32. So 8^2-32=x² x=√32. if the radius is 8 and the one side of the radius is √32 it would be 8-√32. and the other line touching the shaded area it √128 so we can say that the area of the non-little circle is the area of the whole circle-the almost circle. The area of the whole circle it 8^2*pi≈201.06. The area of the almost circle is 201.06*.75=150.79 because 270/360=.75 plus the area of the triangle (32) so the area is 182.79. So the area of the little thing is 201.06-182.79=18.27 divided by 2 =9.13

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: