To win a lottery, 6 numbers are drawn at random from a pool of 63 numbers. numbers cannot repeat. if a person has one ticket, what is the probability that they have the winning ticket?

1 chance in 67 945 521 that's about 1 chance in 57 million

Step-by-step explanation:

Very very small.

The way to choose 6 numbers out of 63 in any order is

63C6

which means

63!/ [ (63 - 6)! 6! ]

63 * 62 * 61 * 60 * 59 * 58/6! = 67945521

So he has 1 chance in 67945521

Put another way, 1 person in 5 in the United States would have to buy a ticket for one of them to win the lottery.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15