Fast. 30 points.
the average age of five children is 6 years old. each child is a different age and there is a difference of two years in the ages of any two consecutive children. in years, how old is the oldest child?

The age of the oldest child id 7.

Step-by-step explanation:

There are 5 children:

1st Child: 7 Years Old

2nd Child: 6 Years Old

3rd Child: 5 Years Old

4th Child: 4 Years Old

5th Child: 3 Years Old

The ges of any two consecutive children difference is 2 years old: 1st Child and 3rd Child.

Hope this helped! :-)

10

Step-by-step explanation:

Because the ages form an arithmetic progression (an evenly spaced sequence) with an odd number of terms, the median age is the same as the average age. Therefore, the age of the third child is 6, the second child is 8 years old, and the first child is 10 years old.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6