Only 35% of the drivers in a particular city wear seat belts. suppose that 20 drivers are stopped at random what is the probability that exactly four are wearing a seatbelt? (round your answer to 4 decimal places)

Here we have a situation where the probability of a driver wearing seat belts is known and remains constant throughout the experiment of stopping 20 drivers.

The drivers stopped are assumed to be random and independent.

These conditions are suitable for modelling using he binomial distribution, where

where n=number of drivers stopped (sample size = 20)

x=number of drivers wearing seatbelts (4)

p=probability that a driver wears seatbelts (0.35), and

C(n,x)=binomial coefficient of x objects chosen from n = n!/(x!(n-x)!)

So the probability of finding 4 drivers wearing seatbelts out of a sample of 20

P(4;20;0.35)

=C(20,4)*(0.35)^4*(0.65)^16

= 4845*0.0150061*0.0010153

= 0.07382

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

c

step-by-step explanation:

i think because what else can be a sample of every member