In the morning, a cow produced 2 3 5 liters of milk, and in the evening it produced 3 3 10 liters more than in the morning. how many liters were milked during that day?

urgent urgent urgent urgent urgent

its 8 1/2

Step-by-step explanation: you add 3 3/10 and 2 3/5 then add 2 3/5 again and you get 8 1/2

8 1/2 liters

Step-by-step explanation:

In the morning the cow produced 2 3/5 liters of milk.

In the evening, the cow produced 3 3/10 more than in the morning; this means to find the total amount produced in the evening we add

2 3/5 + 3 3/10

To add these, find a common denominator; the first thing 5 and 10 will both go into is 10.  It takes two 5's to make 10; this means we use two 3's on the numerator, which gives us 2 6/10.

The second fraction is already over 10, so we do not need to change it.

2 6/10 + 3 3/10

Add the whole numbers, then add the numerators; this gives us 5 9/10.  The cow produces 5 9/10 liters in the evening.

To find the total amount produced that day, add this number to the amount in the morning:

5 9/10 + 2 3/5

The common denominator is 10 again.  Changing 2 3/5 to tenths is still 2 6/10:

5 9/10 + 2 6/10 = 7 15/10

15/10 is improper.  10 will go into 15 one time; this is the whole number.  We add this to 7, giving us 8.  This leaves us with 15-10=5 for the numerator:

8 5/10

This simplifies to 8 1/2.

dont understand

step-by-step explanation:

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints