Which transformation was applied to figure a to form figure b?
a. figure a was translated 3 units right and 10 units down to form figure b.
b. figure a was translated 10 units right and 3 units down to form figure b.
c. figure a was reflected across the line m to form figure b.
d. figure a was rotated 90° clockwise about the point n to form figure b.

B

Step-by-step explanation:

Let point N has coordinates (0,0), then figure A has vertices at points (-3,0), (-7,0), (-7,4) and (-3,4). Figure B has vertices at points (3,1), (7,1), (7,-3) and (3,-3).

1. Translation 10 units to the right has the rule

(x,y)→(x+10,y).

Then vertices of the figure A have images:

2. Translation 3 units down has the rule

(x,y)→(x,y-3).

Then images are

As you can see these points are exactly the vertices of the figure B.

B. Figure A was translated 10 units right and 3 units down to form figure B.

Step-by-step explanation:

We are given two figures (both are squares) and we are to determine whether which transformations were applied to figure A to form figure B.

Initially, the coordinates of figure A were:

(-3, 0), (-7, 0), (-3, 4) and (-7, 4)

And the following coordinates when it transformed to figure B:

(3, 1), (7, 1), (3, -3) and (7, -3)

So basically figure A was translated 10 units right and 3 units down to form figure B.

Therefore, the correct answer option is B.

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

the answer is the third / last answer

step-by-step explanation: