Can anyone explain the graphing method? for example,

it would if you gave me a solved example as well!

you can graph this on a graphing calculator if you have one. if you don't you can use and app called (SymboLab) it's really helpful for all types of mathematical operations. Anyway, for your question, you need to clear you equation first before graphing by isolating Y on a side and other stuff into the other side and as follows:

5y=6-3x ==> y=3(2-x)/5. then you'd be able to graph it either on a graphing calculator as I mentioned by simply pluging it in, or you can do it manually by plugging in bunch of values for X and so you get values for Y, then u use it to plot your graph which is going to be a straight line.

hope this was helpful

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

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im not sure