Ralp has completed 7 successive rounds
The initial amount Raph has was 100 coin
The final amount he had was 415 coin
The difference is (415-100) = 315coin.
Since every successive round won by raph yields him 45coins, therefore,
Ralph had won 315/45 rounds = 7 rounds.
0.04 or 1/25
Note that 25^3 = 15625.
Then 15625k = 625.
Solve for k using division:
k = 625 / 15625 = 0.04
Note that we could also do the problem in this manner:
25 = 5^2
625 = 5^4
Therefore, 5^4 * k = 5^2
Dividing both sides by 5^4, we get:
k = = 5^(2-4) = 5^(-2) or = 1/25 = 0.04 (same as before)
This is a linear equation.
Did you really mean ? I just want to make sure since you said something about a quadratic in your question.
can be simplified to .
This is a linear equation since the exponent on all the variables we have is 1.
To solve for t we are going to subtract 4 on both sides:
Graphical method of solving polynomial equation cannot identify the imaginary roots.
In graphical method, we plot the graph of the polynomial whose roots are to be calculated.
And where the graph intercepts the x-axis, those points are the real roots of the corresponding polynomial.
But in case we need to find the complex or imaginary roots the graphical method fails because we can only find real roots using the graphical, method of solving polynomial equations.
Hence, Graphical method of solving polynomial equation cannot identify the imaginary roots.
k= 2/3 2 over 3.
x > 1⅘
(⅔)x - ⅕ > 1
(⅔)x > 1⅕
(⅔)x > 6/5
x > 6/5 × 3/2
x > 9/5
x > 1⅘
x = 4
Start with your given equation.
4x - 10 = 6
Add 10 on both sides of the equation.
4x = 16
Divide 4 on both sides of the equation and solve.
x = 4
56/8 = 7
Aziza age should be 15 yrs old
the dimensions are:
we want to find the dimensions of a rectangular box with volume of
we factor to obtain;
we rewrite the rightmost factor to obtain;
we apply difference of two squares formula to obtain;
hence the dimensions are
70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)
the lenght is : 35 y^8
the width is : 15y^6