Write the equation of a line that is perpendicular to the given line and that passes through the given point. y-3=8/3(x+2); (-2,3)

Step-by-step explanation:

Ths point-slope form of an equation of a line:

m - slope

(x₁, y₁) - point

We have the equation:

Therefore the slope is

Let k: y = m₁x + b₁ and l: y = m₂x + b₂.

l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = -1/m₁

Therefore

The line passes throguh the point (-2, 3).

We have the equation in point-slope form:

5x+10 is the correct one

hope this