Ryan throws a baseball upward with an initial velocity of 12 m/s from a height of 2m above the ground. how long will it take for the baseball to hit the ground? round answer to the nearest 10th of a second.

It will take 2.6 s for the ball to hit the ground.

Step-by-step explanation:

This is a standard physics problem

The equation that defines the movement of Ryans baseball is given by the initial velocity, and the acceleration

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 2m over the ground)

Vo is the initial velocity = 12m/s

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 )

t is the time

We substitute in the equation, and solve for t (time)

(0)=  2+ (12)*t + 0.5*(-9.8)*t^2

We get that

t = 2.606 s  = 2.6 s

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.