I'm struggling in algebra 2 right now! can someone explain how to work out

i'm a "why" learner so if you can put a few small explanations here and there, do! you don't have to though!

First of all, we *do* have to put explanations, so it's good that you want them, keep this attitude going!

As for the excercise, we want to use the property that allows us to swap sum/subtractions of logarithm into multiplication/division inside them:

So, we want to move all logarithmic terms to the left hand side: add to both sides to get

Now we can use the property we just invoked:

This is a good position, because every equation of the form

can be solved by considering both sides as the exponents of the base of the logarithm:

(I used the fact that exponential and logarithm are the inverse one of the other: )

So, we can conclude

This is a standard quadratic equation, whose solutions are (I assume you are confident in solving this kind of equation, let me know otherwise)

Finally, we have to check if these solutions can actually be fed in the equation: we have

which is true. On the other hand,

But this expression can't be computed, because you can't compute the logarithm of a negative number. So, the only feasible solution is

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

the answer is c. 23/3