Explain why the equation (x-3)^2-38=11 has two solutions. then solve the equation to find the solutions. show your work.

X = 10 and X = -4

Step-by-step explanation:

(x-3)^2-38=11

(x-3)^2 = 11 +38

(x-3) ^2 = 49

Taking square root on both sides

√(x-3) ^2 = √ 49

X-3 = +7, -7

X = 7 +3,    X= -7+3

X = 10        X = -4

So, it has got two solutions

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: