David leaves the house to go to school he walks 200m west and 125 m north how far is he from his starting point

235.8

Step-by-step explanation:200²m +125²=55625

c²=55625

c=√55625≈235.8

David is 235.85 meters away from starting point.

Step-by-step explanation:

To get the distance David is from starting point, we will apply the Pythagoras theorem.

Let the distance he is away from starting point be x.

=>

=>

x =

= 235.85 meters

Therefore, David is 235.85 meters away from starting point.

Note: If you need to round this to nearest whole number, it will be 236 meters.

the workers who do no drive has no reasonable reason to buy gasoline due to they don't have anything to use it for

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!