![\text{use}\\\\a^{-n}=\dfrac{1}{a^n}\\\\==========================\\\\b^{-3}=\dfrac{1}{216}\\\\\dfrac{1}{b^3}=\dfrac{1}{216}\qquad\text{inverse both sides}\\\\b^2=216\to b=\sqrt[3]{216}\\\\b=6\ \text{because}\ 6^3=216](/tpl/images/0441/4406/c1ae0.png)
Which value of b solves the equation?
b^-3 = 1/216
a. –6 b. 6 c. 36 d. 72...
Mathematics, 03.01.2020 17:31, markellg1128
Which value of b solves the equation?
b^-3 = 1/216
a. –6 b. 6 c. 36 d. 72
Answers: 3
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