(n + -2 ) x ( n - -4 ) = 27

what are the two n's?

Simplify n + -2 to n - 2

(n - 2)(n + 4) = 27

Expand

n^2 + 4n - 2n - 8 = 27

Simplify n^2 + 4n - 2n - 8 to n^2 + 2n - 8

n^2 + 2n - 8 = 27

Move all terms to one side

n^2 + 2n - 8 - 27 = 0

Simplify n^2 + 2n - 8 - 27 to n^2 + 2n - 35

n^2 + 2n - 35 = 0

Factor n^2 + 2n - 35

(n - 5)(n + 7) = 0

Solve for n

n = 5, -7

9 and 3

Step-by-step explanation:

27/3=9

There are 2 different ways to solve this equation.

Side note: subtracting a negative (4- -3) turns the equation into addition (4+3) and adding a negative (4+ -3) turns the equation into subtraction (4-3)

So the original equation: (n + -2)x(n - -4)=27

Turns into this: (n-2)x(n+4)=27

Way 1: (11-2)x(-1+4)=27

9x3=27

Way 2: (5-2)x(5+4)=27

3x9=27

Hope this helped! :)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.