Can someone me solve this problem ?

See below

Step-by-step explanation:

Let the original fraction be (x - 3) / x, then:

(x - 3) / x + (x - 3 + 2) / (x + 2) = 29/30

(x - 3) / x + (x - 1) / (x + 2) = 29/30

Multiply through by the LCD 30x(x + 2) we have:

30(x - 3)(x+ 2) + 30x (x - 1) = 29x(x + 2)

30(x^2 - x - 6) + 30x^2 - 30x = 29x^2 + 58x

30x^2 - 30x - 180 + 30x^2 - 30x = 29x^2 + 58x

60x^2 - 29x^2 - 60x - 58x - 180 = 0

31x^2 - 118x - 180 = 0

The solutions to this are not integers which makes me think there might be a mistake in the question...

The solutions of the last equation are x = 4.97 or -1.17.

answer: i guess 5 units?

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752