The perimeter of a rectangle is 36m. if its length is increased by 1m and the width is increased by 2m, its area will increase by 30m^2. find the area of the original rectangle.

  80 m^2

Step-by-step explanation:

The given information lets you write two equations involving length (x) and width (y).

The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.

  xy +y +2x + 2 -xy = 30

  2x +y = 28 . . . . . . . subtract 2

Dividing the first equation by 2 gives

  x +y = 18

and subtracting this from the above equation gives ...

  (2x +y) -(x +y) = 28 -18

  x = 10

Then

  y = 18 -10 = 8

The area of the original rectangle is xy = 10·8 = 80 m^2.

y > 1/3x

y < = -x + 4

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step-by-step explanation:

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