Mathematics, 18.11.2019 20:31, katelynn73
The polynomial (s+1)x^2 - (s-2)x + 1 is a perfect square. find the value(s) of s.
Answers: 2
![\bf \stackrel{\textit{product of 2 and the }\sqrt{\qquad }\textit{ of other terms}}{2(\sqrt{(s+1)x^2})(\sqrt{1})}~~=~~\stackrel{\textit{middle term of the trinomial}}{(s-2)x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2\sqrt{(s+1)x^2}=(s-2)x\implies 2x\sqrt{s+1}=(s-2)x\implies 2\sqrt{s+1}=s-2](/tpl/images/0379/9189/924fd.png)
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The polynomial (s+1)x^2 - (s-2)x + 1 is a perfect square. find the value(s) of s....
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