The numbers 1 through 10 are written in separate slips of paper, and the slips are placed into a box. then, 4 of these slips are drawn at random.
what is the probability that the drawn slips are "1", "2", "3", and "4", in that order

Since you want those numbers to appear in that precise order, you only change is to extract 1 with the first draw, 2 with the second, and so on.

You have 10 slips at the beginning, so the probability of having 1 at the first draw is

Now you have 9 slips left, so the probability of picking 2 with the second draw is

Similarly, the remaining probabilities are and

You want these events to happen one after the other, and they are independent. So, the overall probability is the product of the single probabilities:

no, because the sides are not congruent

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.