Qiulian and tammy have 2400 cards. tammy has twice as many cards as quilian. how many cards must tammy give quilian so that they have the same number of cards?

400 Cards

Step-by-step explanation:

Before we find out how many cards Tammy needs to give to Quilian to have the same number of cards, we first need to find how many cards they currently have.

Let x = Quilian's Cards

Let 2x = Tammy's Cards

Now we can use the equation:

x + 2x = 2400

This represents both Tammy and Quilian's cards together.

Now we can solve for Quilian's cards first.

x + 2x = 2400

Now that we know that Quilian has 800 cards, we can safely assume that Tammy would have:

2x = 2(800) = 1600 Cards

Now that we know how many cards both of them have we simply need to subtract the number of cards that Tammy has until we reach 1/2 the amount of the total amount.

2400 / 2 = 1200

1600 - 1200 = 400 Cards

So Tammy would have to give Quilian 400 cards to make them have the same number of cards.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b