Ahula hoop has a three foot diameter how far will it travel in 6 revolution

Distance traveled in 6 revolution = 56.52 ft

Step-by-step explanation:

Formula:

Circumference  of circle = 2πr

r - Radius of circle

It is given that,

A hula hoop has a three foot diameter.

Diameter = 3 ft

Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

To find the circumference of loop

r = 1.5 ft

Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

To find the distance traveled in 6 revolution

Distance traveled in one revolution =  9.42 ft

Distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)