If u=< -4,8> and v=< -7,5> , v-5u= ? and ||v-5u|| is approximately?

Step-by-step explanation:

a) Given:

u=

v=<-7,5>

v-5u=<-7,5>-5<-4,8>

v-5u=<-7,5>+<20,-40>

v-5u=<-7+20,5-40>

v-5u=<13,-35>

b)

The magnitude of this vector is

||v-5u||=

||v-5u||=

||v-5u||=

||v-5u||= to the nearest tenth

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5