Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. the function of the ball's height (h) at time (t) seconds after launch is h(t) = -2t^2+34t+28. determine how long it will take for the ball to be at its original height.

17 seconds

Step-by-step explanation:

h(t) represents height, we want to know when the ball will return to a height of 28 feet.  So our equation is..

28 = -2t² + 34t + 28

Now solve for t...

0 = -2t² + 34t         (subtract 28 from both sides)

0 = t² - 17t             (divide both sides by -2)

0 = t(t - 17)          (factor out a t)

So

t = 0

or

t - 17 = 0

  t = 17          

0 seconds is the initial height.  At 17 seconds, the ball will return to that height

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d