Aball is kicked 4 feet above the ground with an initial vertical velocity of 51 feet per second. the function h(t)=−16t2+51t+4 represents the height h (in feet) of the ball after t seconds. using a graph, after how many seconds is the ball 28 feet above the ground? round your answers to the nearest tenth. i'd like to ask for the answer and the steps to get there. you!

Check the first picture below.

now, the exercise states to get it from the graph, so we have to graph it first.

Check the second picture below.

recall, the height in feet is on the y-axis, and the time in seconds is on the x-axis.

and rounded up to the nearest tenth will be 0.6.

was it correct when u put it in?

Step-by-step explanation:

im doing the same question now and u wanna make sure its right

step-by-step explanation: