Find the perimeter of a square with an area of 702.25

area of a square= 702.25

A= side square

let's take side of a square= a

therefore,

702.25= a^2

a= √702.25 = 26.5

perimeter (P) of a square= 4a

P = 4x 26.5= 106

so perimeter of a square is 106

the balance is found at the link

step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.