50 points, 3 questions and explain your answer

See below.

Step-by-step explanation:

Two

Up to the fourth line is correct. The fifth line contains the error.

Line four take the square root of both sides.

sqrt(x-3)^2 = sqrt(16)

x - 3 is correct = +/- 4

x - 3 = 4

x = 3 + 4

x = 7

x - 3 = - 4

x = -4 + 3

x = - 2

The two answers should be (7,0) and (-2,0)

Three

x^2 - 4x + 3 = 0

This equation factors without the use of the quadratic formula

(x - 3)(x - 1) are its two factors.

So the two points are (3,0)(1,0). However I will be obedient to what you were asked for

a = 1

b = -4

c = 3

x  = [- b +/- sqrt(b^2 - 4ac)] / (2a)

x = [ -(-4) +/- sqrt(4^2 - 4(1)(3)]/(2*1)

x = [4 +/- sqrt(16 - 12) ] / 2

x = (4 +/- 2) / 2

x = 2 /2 = 1

or

x = 6/2 = 3

Question 4

(x - 4)^2 - 28 = 8                     Add 28 to both sides

(x -4)^2 - 28 + 28 = 8 + 28     Combine like terms on the left and right

(x - 4)^2 = 36                           Take the square root of both sides.

x - 4 = +/- 6

x - 4 = 6

x = 6 + 4

x = 10

x - 4 = - 6

x = -6 + 4

x = - 2

The two points which are solutions are

(10,0)(-2,0)