Aball, dropped vertically, falls d metres in t seconds. d is directly proportional to the square of t. the ball drops 80 metres in the first 4 seconds. how far does the ball drop in the next 8 seconds?

640 m.

Step-by-step explanation:

D = kt^2  where d is the constant of proportionality.

D = 80 m when t = 4 seconds so:

80 = k*4^2

k = 80 / 16 = 5.

So the equation of motion is D = 5t^2.

When t = 8+4 = 12 seconds D = 5*12^2 =  5*144

=  720 m

So the distance the ball drops in the next 8 seconds = 720 - 80

= 640 m.

The distance covered by the ball in the next 8 seconds will be 320 meters.

Given information:

A ball, dropped vertically, falls D meters in t seconds.

D is directly proportional to the square of t.

The ball drops 80 meters in the first 4 seconds.

So, the relation between D and t can be written as,

where k is the constant.

Now, from the given condition, the value of k can be calculated as,

Now, the distance covered by the ball in the next 8 seconds will be,

Therefore, the distance covered by the ball in the next 8 seconds will be 320 meters.

For more details, refer to the link:

link

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

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