The area of a rectangular lot is represented by 6t^2+13t-5. what are the length and width of the rectangular lot ?

(3t-1) and (2t+5)

Step-by-step explanation:

In order to get the length and width of the lot, you need to factor this quadratic in order to get two factors that multiply to the quadratic. The quadratic being factored is 6t^2+13t-5. First, multiply the coefficient of 6t^2 (6) or your a value by your c value (-5) This gets you to -30. Now, you need to find two values that both add to your b value (13) and multiply to your a times c value (-30). These two values are 15 and -2. Now you're left off with 6t^2+15t-2t-5. Now with four terms in the equation, you can group them into pairs of two, leaving you with 6t^2+15t and -2t-5. Now, we need to factor out as much as we can from 6t^2+15t. Both terms are divisible by 3 and both have at least one t in them, so we can divide the terms by 3t to make 3t(2t+5). Now we must divide the other set of terms into something that gets us 2t+5. The terms are -2t-5, which can be divided by -1 to get 2t+5. Now we have 3t(2t+5)-1(2t+5). Combine the 3t and -1 to get 3t-1, and leave the 2t+5 as your other factor. This means that you end up with (3t-1)(2t+5)

his chances of getting a coin of higher value is 4/19

step-by-step explanation: