Determine a radical function that starts at the point (-4,2) and goes to the right and decreases. the domain is all x> -4 and the range is all y< 2. explain how you determined you function.

f(x) = -√(x-4) + 2

Step-by-step explanation:

(a) Start with the basic function: f(x) = √x.

This would be the top half of a horizontal parabola opening to the right (always positive).

(b) The range is y < 2. This includes negative numbers, so the function must be f(x) = -√x.

(c) The function starts at x = -4. We must shift it four units to the left. We do that by adding four units to x. The function must be f(x) = -√(x + 4). The domain is x > -4.  

(d) The function starts at y = 2. We must shift it up two units. We do that by adding two units to y. The function must be f(x) = -√(x+4) + 2. The range is y < 2.

The figure below is the graph of f(x) = -√(x+4) + 2.  

h

step-by-step explanation:

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.