Me if you can

identify the graph of the system of constraints then find the values of x and y that maximize the objective function.

The maximum is at (0,4)

Step-by-step explanation:

x≥0

y≥0

x+y ≤4

2x+y ≤6

We need to plot the four inequalities.  The left side has no axis.  The max is at 4.  The minimum is at 0  for the shaded area

When we have a system of constraints, the minimum and maximum are at the vertices of the graph

There are 4 points

(0,0)

The intersection point of the 2 lines which is (2,2)

The intersection at the y axis (0,4)

The intersection at the x axis is (3,0)

Once we have these points we put them into the constraint equation

C = 30x+50y

(0,0)

C = 0+0 = 0  This would be the trivial point since nothing happens

(0,4)

C = 0+50(4) = 200

(3,0)

C = 30*3 = 90

(2,2)

C = 30(2) + 50(2) = 60+100 = 160

The maximum is at (0,4)

lolololkzaxio2ier286udeg

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58