Mathematics, 04.02.2020 23:01, mfox793

Quick anyone know the answer to this algebra question?

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answered: Answers4833

$\bold{b)\ \dfrac{-3\cdot a^7\cdot b^3\cdot b^1}{15\cdot a^2} }$

Step-by-step explanation:

Move the term that has a negative exponent to the other side of the fraction bar. This changes the negative exponent to a positive exponent.

$\dfrac{-3\cdot a^{-2}\cdot b^3}{15\cdot a^{-7}\cdot b^{-1}}\\\\\\\text{move }a^{-2}\text{ to the bottom and }a^{-7}\text{ to the top. Change the sign of the exponent.}\\\\\dfrac{-3\cdot a^7\cdot b^3}{15\cdot a^2\cdot b^{-1}}\\\\\\\text{move }b^{-1}\text{ to the top. Change the sign of the exponent.}\\\\\dfrac{-3\cdot a^7\cdot b^3\cdot b^1}{15\cdot a^2}$

answered: Guest

step-by-step explanation:

domit

answered: Guest

ratios represent a pattern or relationship that can be scaled.

equivalent ratios are pairs of ratios that represent the same relationship between quantities, and can be generated by multiplying or dividing both quantities in the ratio by the same factor.

in this lesson, students will use double number lines and ratio reasoning to solve ratio problems. by partitioning double number lines into proportionate intervals, students will build an understanding of equivalent ratio relationships as those that are generated by multiplying or dividing two related quantities by the same number. this lesson will build upon students' prior understanding of multiplicative comparisons, number line reasoning and equivalent fractions (while highlighting the difference between equivalent fractions and equivalent ratios); and will build toward future work in this unit on building ratio tables, and work in future grades in proportionality, scaling, and expressing and graphing linear functions.

step-by-step explanation:

ratios represent a pattern or relationship that can be scaled.

equivalent ratios are pairs of ratios that represent the same relationship between quantities, and can be generated by multiplying or dividing both quantities in the ratio by the same factor.

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